php - cannot pass argument [solved]

[Leo]

I am attempting to get to know php but cannot get the simplest of pages to work.

 

I have installed apache 2.0.54 and php 5.0.4

 

I have copied a script:

<?php
if (!isset($page)) $page = 'default.html';

$page = "$page";
$fp = fopen($page,"r");
$content = fread($fp, filesize($page));
fclose($fp);

$content = str_replace('[HEADER]','<?php include\'header.php\';?>', $content);
$content = str_replace('[FOOTER]','<?php include\'footer.php\';?>', $content);
$content = str_replace('[NEWSLETTERSIGNUP]','<?php include\'nlsignup.php\';?>', $content);
eval('?>'.$content);
?>

and the relevant html files as well as an html file called welcome.html:

[HEADER]

Welcome to some text

[NEWSLETTERSIGNUP]

[FOOTER]

When I attempt to display the file however using

http://localhost/default.php?page=welcome.html

in firefox, nothing is displayed.

 

My apache log shows the following errors:

[client 127.0.0.1] PHP Warning:  fopen(default.html) [<a href='function.fopen'>function.fopen</a>]: failed to open stream: No such file or directory in /var/www/html/default.php on line 6
[client 127.0.0.1] PHP Warning:  filesize() [<a href='function.filesize'>function.filesize</a>]: stat failed for default.html in /var/www/html/default.php on line 7
[client 127.0.0.1] PHP Warning:  fread(): supplied argument is not a valid stream resource in /var/www/html/default.php on line 7
[client 127.0.0.1] PHP Warning:  fclose(): supplied argument is not a valid stream resource in /var/www/html/default.php on line 8

all the files are saved under /var/www/html.

If I amend the code to set $page to the welcome.html file then it all works, but it will not allow me to pass in the file as an argument.

 

I hae a suspicion that it is my setup that is wrong but do not know where to start.

 

Any help would be grtatefully received.

 

thanks

Leo

Edited August 27, 2006 by Leo

[Steve Scrimpshire]

You have to set $page. Just passing it in the url is not enough:

$page = $_GET['page'];

 

Or something like that.

[Leo]

cool.

 

That works perfectly.

 

Thanks

Leo